Strip Url Params

Strip Url ParamsCodewars

Approach

1. extract domain

2. extract query

   1. find query string part through ? string

   2. split through '=' cvs

   3. reducing process-2-2, with object

      1. if object already has key or belongs to exception rule pass, if not add to reducing value

3. if process-2 has result return process-1 + process-2 else return process-1

Solution

JavaScript

const stripUrlParams = (url, paramsToStrip = []) => {
  const domain = url.indexOf('?') !== -1 ? url.substr(0, url.indexOf('?')) : url;
  const query = url.slice(url.indexOf('?') + 1).split('&')
    .reduce((acc, cur) => {
      let [key, value] = cur.split('=');
      if (!acc[key] && !paramsToStrip.includes(key)) {
        acc[key] = value;
      }
      return acc;
    }, {});
  
  return !Object.keys(query).length || url.indexOf('?') === -1 ? domain :
    `${domain}?${Object.entries(query).map((v) => v.join('=')).join('&')}`;
};