Geometry Basics: Distance between points in 2D

Geometry Basics: Distance between points in 2DCodewars

Approach

Solve the problem - pythagorean theorem

1. return squre root of | a.x - b.x |**2 + | a.y - b.y |**2

advanced solution

in JavaScript Math class there is method for this

Math.hypot() - JavaScript | MDN

above expression has some problem (I guess that's library problem)

so I hand wrote that

Solution

pythagorean theorem

JavaScript

const distanceBetweenPoints = (a, b) => {
  return Math.sqrt(Math.abs(a.x - b.x) ** 2 + Math.abs(a.y - b.y) ** 2);
};

Best practice on codewars - use Math.hypot

JavaScript

function distanceBetweenPoints(a, b) {
  return Math.hypot(a.x - b.x, a.y - b.y);
}