Playing with Sets : Sup/Sub

Playing with Sets : Sup/SubCodewars

Approach

Find pattern

• when a has all elements of b a is superset of b in other words, b is A subset of a

Solve the problem

• iterate A element and check all elements belongs to B, if true A is a subset of B, in other words, B is a superset of A

Solution

JavaScript

const isSubsetOf = (s1, s2) => ![...s1.values()].some((v) => !s2.has(v));

const isSupersetOf = (s1, s2) => isSubsetOf(s2, s1);